We can choose any position to be our starting point, so for simplicity's sake, I will use the original starting position of the block at the top of the incline.Īfter substituting known values, we arrive at the following equation: Because the loop has r = 1.0 m, that means that at position C, the top of the loop, the block is 2r above the ground, or 2 * 1.0 m = 2.0 m. The velocity of the block at the bottom of the incline is therefore 9.90 m/s.įinally, we can use the same conservation of energy equation to solve for the velocity of the block at the top of the loop. Using the equation KE = mv 2/2, we can solve for the speed by substituting 4 kg for the mass: Therefore, our simplified conservation equation would look like the following: Similarly, once the block is at the bottom of the incline, its final potential energy is equivalent to 0, because h = 0. Since the block starts from rest, KE i = 0. Next, we can use our conservation of energy equation to determine the velocity of the block at the bottom of the incline. Therefore, PE of the block at point A = 4*5*9.8 = 196 J. Mass of block = 4 kg, h = 5 m, and g = 9.8 m/s 2 Here, potential energy is equivalent to mgh, so we can use that to find the initial potential energy of the block at point A: Because there is no friction, we can write our energy equation as the following: You may also find the following Physics calculators useful.Hi Gavin! This problem deals primarily with the conservation of energy.
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